A box was measured with a degree of accuracy to the nearest 2cm; 24cm Γ— 24cm Γ— 20cm. What is the smallest possible volume of the box to the nearest cm3?

Accepted Solution

Each measurement is accurate to 2cm so they can each be β€œoff” by 2. Since we want the smallest possible volume let’s assume each is actually 2 less than what is given.

The sides would then measure: 22, 22 and 18cm respectively. We obtain the volume by multiplying length, width and height...the three values given.

Thus the smallest volume is 22x22x18=8,712 cm^3